TheTechGuide Forum

General Category => Software => Topic started by: Anonymous on August 22, 2002, 08:56:13 AM

Title: Windows Boot Menu
Post by: Anonymous on August 22, 2002, 08:56:13 AM

How does Microsoft make their CDs boot, then if you don\'t select booting to the CD in a certain amount of time, then it defaults to booting your hard drive...whether you have an O/S or not?

This avoids install looping.

Title: Windows Boot Menu
Post by: quietkey on August 26, 2002, 09:42:42 AM

The answer to that question is located in the HowTo section, under making a bootable Win2k Install CD.  Wish I could use that to make EVERY cd prompt, but unfortunately, it\'s just the 2k Install CD.

Title: Windows Boot Menu
Post by: Space Between on August 26, 2002, 03:42:01 PM

What does this have to do with a boot menu??? your talking the boot sequence...and that would be by following the IBM El Torito standards on creating bootable devices, harddrives\', cd\'s, BIOS\'s, etc....

This information is free for anyone to know

Title: Windows Boot Menu
Post by: Twinkie on August 26, 2002, 05:51:01 PM

It\'s a hex value in the bootfix.bin file I think... or maybe boot.bin.  Whatever .bin file it boots off of anyway.  Long day...

Anyway, if you can read assembler code you should be able to make sense of it.  That is how the files are written.  At least that was how Bart explained it to me.  Use the pages below to find out more...

http://www.nu2.nu/bootcd/ (http://\"http://www.nu2.nu/bootcd/\")
or
http://www.phoenix.com/resources/specs-cdrom.pdf (http://\"http://www.phoenix.com/resources/specs-cdrom.pdf\")
or
http://www.cdpage.com/Compact_Disc_Variations/danaboot.html (http://\"http://www.cdpage.com/Compact_Disc_Variations/danaboot.html\")