Dear everybody,
Please help me to declare in autoexec.bat.
I plan to make a bootable Win98SE Cd that when it boots, it will automatically run a program. I know how to make a bootable CD but I don't know how to declare in autoexec.bat because this CD when run on this PC, the CD drive may be drive E but when run on other PC, the CD drive may be F.
Therefore, I don't know how guide the CD to define exactly the execute file located.
I don't use the image file because this program is bigger than 5 MB.
Anybody knows, please help me
Thanks a lot
Tung